There are only few numbers satisfying the 1st property and for them I
checked using python the second condition. :)
Competition name - Codematics

On Sun, Feb 27, 2011 at 1:18 AM, Rel Guzman Apaza <[email protected]> wrote:

> what competition?
>
> 2011/2/26 Gunjan Sharma <[email protected]>
>
> As the competition is over I can reveal u the answer. There is only one
>> number satisfying given condition and that is 578 so the answer is 20 :)
>>
>>
>> On Fri, Feb 25, 2011 at 10:33 PM, vaibhav shukla <[email protected]
>> > wrote:
>>
>>> nothing to do with complexity...
>>> just the ans
>>>
>>>
>>> On Fri, Feb 25, 2011 at 10:23 PM, Rel Guzman Apaza <[email protected]>wrote:
>>>
>>>> Is there a maximum time complexity?
>>>>
>>>> 2011/2/25 vaibhav shukla <[email protected]>
>>>>
>>>>> Find the sum of digits of all the numbers whose digits are all in
>>>>> ascending order from left to right. All these numbers lie between 500 to
>>>>> 1000 and satisfy M divides (M-1)* !* + 1 , where M is any natural
>>>>> number.
>>>>> (* " ! " * denotes factorial of the number)
>>>>> --
>>>>>
>>>>>
>>>>>
>>>>> best wishes!!
>>>>> Vaibhav Shukla
>>>>>     DU-MCA
>>>>>
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>>>
>>>
>>>
>>> --
>>>   best wishes!!
>>> Vaibhav Shukla
>>>     DU-MCA
>>>
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>>
>>
>>
>> --
>> Regards
>> Gunjan Sharma
>> Chairman IEEE Students Chapter IIT Roorkee
>> B.Tech IV year CSE
>>
>> Contact No- +91 9997767077
>>
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