what competition?

2011/2/26 Gunjan Sharma <[email protected]>

> As the competition is over I can reveal u the answer. There is only one
> number satisfying given condition and that is 578 so the answer is 20 :)
>
>
> On Fri, Feb 25, 2011 at 10:33 PM, vaibhav shukla 
> <[email protected]>wrote:
>
>> nothing to do with complexity...
>> just the ans
>>
>>
>> On Fri, Feb 25, 2011 at 10:23 PM, Rel Guzman Apaza <[email protected]>wrote:
>>
>>> Is there a maximum time complexity?
>>>
>>> 2011/2/25 vaibhav shukla <[email protected]>
>>>
>>>> Find the sum of digits of all the numbers whose digits are all in
>>>> ascending order from left to right. All these numbers lie between 500 to
>>>> 1000 and satisfy M divides (M-1)* !* + 1 , where M is any natural
>>>> number.
>>>> (* " ! " * denotes factorial of the number)
>>>> --
>>>>
>>>>
>>>>
>>>> best wishes!!
>>>> Vaibhav Shukla
>>>>     DU-MCA
>>>>
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>>>
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>>
>>
>>
>> --
>>   best wishes!!
>> Vaibhav Shukla
>>     DU-MCA
>>
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>
>
>
> --
> Regards
> Gunjan Sharma
> Chairman IEEE Students Chapter IIT Roorkee
> B.Tech IV year CSE
>
> Contact No- +91 9997767077
>
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