@sandeep sir: thanx sir for clearing doubt....

On 7/12/11, Sandeep Jain <sandeep6...@gmail.com> wrote:
> *const* in C++ is not exactly same as *final* in java. SO unlike java adding
> the keyword const to a function does not affect overriding.
> Infact, adding in C++ const functions ==> that they will not modify any
> member of the class.
> non-const functions cannot be invoked by const objects.
>
> Try making object 'a' as const i.e.
> const x a;
> and then invoke f(), it should invoke the correct version.
>
> Note that C++ allows function overloading based on const-ness.
> Refer (Const function section)
> http://www.cprogramming.com/tutorial/const_correctness.html
> Also, subscript operators generally come in pairs, Refer
> http://www.parashift.com/c++-faq-lite/operator-overloading.html#faq-13.10
> http://www.parashift.com/c++-faq-lite/const-correctness.html#faq-18.12
>
>
> Regards,
> Sandeep Jain
>
>
>
> On Tue, Jul 12, 2011 at 10:09 PM, dheeraj tyagi
> <dheeraj2...@gmail.com>wrote:
>
>> const means that it cannot be overloaded..i think due to that this is
>> happening.
>>
>>
>> On Tue, Jul 12, 2011 at 9:26 PM, segfault <pawan1991ya...@gmail.com>wrote:
>>
>>> #include<iostream>
>>> using namespace std;
>>> class x{
>>> public:
>>> x() {}
>>>
>>> int  func() const{
>>> cout<<"it is const function\n";
>>> }
>>>
>>> int func() {
>>> cout<<"it is simple functin\n";
>>> }
>>>
>>>
>>> };
>>> int main()
>>> {
>>> x a;
>>> a.func();
>>> return 0;
>>> }
>>>
>>> why cann't it take const function?
>>> explain it
>>>
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>>
>>
>> --
>> With regards
>> Dheeraj Tyagi
>> 8197218001
>>
>>
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