Hi,
In first program,it will call copy constructor once, while returning object
by value.
In 2nd program it will call copy constructor twice, once when u pass an
object to function by value, and 2nd time when you return an object by value
from function.
Thanks.
On Tue, Jul 12, 2011 at 11:52 PM, segfault <pawan1991ya...@gmail.com> wrote:
> #include<iostream>
> using namespace std;
> class x{
> int p;
> public:
> x(){cout<<"constructor\n";}
> x(const x &y)
> {
> cout<<"copy constructor\n";
> }
> ~x()
> {
> cout<<" destructor\n";
> }
> void print()
> {
> cout<<"print statement\n";
> }
> };
> x g()
> {
> x b;
> b.print();
> return b;
> }
> int main()
> {
> x b;
> x t=g();
> }
>
>
>
> #include<iostream>
> using namespace std;
> class x{
> int p;
> public:
> x(){cout<<"constructor\n";}
> x(const x &y)
> {
> cout<<"copy constructor\n";
> }
> ~x()
> {
> cout<<" destructor\n";
> }
> void print()
> {
> cout<<"print statement\n";
> }
> };
> x g(x b)
> {
>
> b.print();
> return b;
> }
> int main()
> {
> x b;
> x t=g(b);
> }
>
>
> why first one is not calling copy constructor in function g() while
> returning from it
> but second one is calling copy constructor in function g() while
> returning from it?
>
> in both program inside g() b is local but why giving different result.
>
> bruce ackel page number:467
>
>
>
> please explain it.
>
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