#include<iostream>
using namespace std;
class x{
int p;
public:
x(){cout<<"constructor\n";}
x(const x &y)
{
cout<<"copy constructor\n";
}
~x()
{
cout<<" destructor\n";
}
void print()
{
cout<<"print statement\n";
}
};
x g()
{
x b;
b.print();
return b;
}
int main()
{
x b;
x t=g();
}
#include<iostream>
using namespace std;
class x{
int p;
public:
x(){cout<<"constructor\n";}
x(const x &y)
{
cout<<"copy constructor\n";
}
~x()
{
cout<<" destructor\n";
}
void print()
{
cout<<"print statement\n";
}
};
x g(x b)
{
b.print();
return b;
}
int main()
{
x b;
x t=g(b);
}
why first one is not calling copy constructor in function g() while
returning from it
but second one is calling copy constructor in function g() while
returning from it?
in both program inside g() b is local but why giving different result.
bruce ackel page number:467
please explain it.
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