if that is the case as u say, then wont it be 3+ 4+ 5 when x +3
initially?..and then x increments by one later due to the single post
increment

On Sun, Jul 24, 2011 at 10:15 AM, sagar pareek <[email protected]>wrote:

> nope compiler read it from left to right
>
>
> On Sun, Jul 24, 2011 at 12:05 AM, Arun Vishwanathan <
> [email protected]> wrote:
>
>> @sagar: if what u said previously holds as in when u say y=x++ + ++x is
>> evaluated as 4+4 since ++x results in 4 and 4 is used in x++ too (cos post
>> increment increments x later) then for y=x++ + ++x + ++x with x beginning as
>> 3 shud the expression not be evaluated as 5+5+4( from rhs ++x does a 3 to 4
>> and another ++x does 4 to 5 and 5 is used in x++) .later x becomes 6 ?
>>
>>
>>
>>
>> On Sat, Jul 23, 2011 at 2:39 PM, sagar pareek <[email protected]>wrote:
>>
>>> sorry for above...typo mistake :-
>>>
>>> yup
>>> but what about this
>>> x=3;
>>>  y= x++ + ++x + ++x; // it is executed as:-
>>>
>>> during first addition, increase the value of x, now first addition will
>>> be 4+4 + ++x;
>>> now for second addition it will be like
>>> 8+5
>>> hence final value of y=13;
>>> do it by urself
>>>
>>> On Sat, Jul 23, 2011 at 6:09 PM, sagar pareek <[email protected]>wrote:
>>>
>>>> yup
>>>> but what about this
>>>> x=4;
>>>> y= x++ + ++x + ++x; // it is executed as:-
>>>>
>>>> during first addition, increase the value of x, now first addition will
>>>> be 4+4 + ++x;
>>>> now for second addition it will be like
>>>> 8+5
>>>> hence final value of y=13;
>>>> do it by urself
>>>>
>>>> On Sat, Jul 23, 2011 at 2:54 PM, shady <[email protected]> wrote:
>>>>
>>>>> @sagar
>>>>> would it get evaluated like this ?
>>>>> supposing x = 3;
>>>>>
>>>>> y = x++ + ++x; becomes y = (x=x+1) + (x=x+1);
>>>>> then x=x+1;
>>>>>
>>>>> so x = 5, y = 8;
>>>>>
>>>>> On Sat, Jul 23, 2011 at 2:48 PM, sagar pareek 
>>>>> <[email protected]>wrote:
>>>>>
>>>>>> @Venga
>>>>>> if u are doing this
>>>>>> y= x++ + ++x; //x=3
>>>>>> then it would be
>>>>>> like that :-
>>>>>> ++x; //x=4
>>>>>> y=x+x;
>>>>>> x++;
>>>>>>
>>>>>> i thing this is sufficient  :)
>>>>>>
>>>>>> On Sat, Jul 23, 2011 at 1:20 PM, Interstellar Overdrive <
>>>>>> [email protected]> wrote:
>>>>>>
>>>>>>> The expression y = x++ + x++ + ++y;  is not a valid one. The result
>>>>>>> is compiler dependent
>>>>>>> Read this for reference :http://c-faq.com/expr/seqpoints.html
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
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>>>>>>
>>>>>>
>>>>>> --
>>>>>> **Regards
>>>>>> SAGAR PAREEK
>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>> NIT ALLAHABAD
>>>>>>
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>>>> --
>>>> **Regards
>>>> SAGAR PAREEK
>>>> COMPUTER SCIENCE AND ENGINEERING
>>>> NIT ALLAHABAD
>>>>
>>>>
>>>
>>>
>>> --
>>> **Regards
>>> SAGAR PAREEK
>>> COMPUTER SCIENCE AND ENGINEERING
>>> NIT ALLAHABAD
>>>
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>>
>>
>>
>> --
>> Arun Vish
>> Graduate Student
>> Department of Computer Science
>> University of Southern California
>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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-- 
Arun Vish
Graduate Student
Department of Computer Science
University of Southern California

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