yeah u are right   :)
try this one:-

x=3;
y=++x + (++x + ++x);

answer is y=18   guess why ?

On Mon, Jul 25, 2011 at 2:27 PM, Arun Vishwanathan
<[email protected]>wrote:

> thanks sagar!
> so just to confirm ,what i get from above is that the x value before the
> first addition is first updated from 3 to 5( due to 2 pre increments) and
> then 5 and  5 is added to make the 10.This is then added to 6( as before the
> second addition x is updated again)
>
> if y = x++ + ++x + x++
> then will the value seem like for the first addition(x++ + ++x ) as
> 4+4?(since the single pre increment increases the value of x by 1) ,and then
> for the next addition it would be 8+4(since post increment here so x doesnt
> change)?finally the value of x is 6?
> pls correct me if wrong ...
>
>
>
>
> On Mon, Jul 25, 2011 at 10:21 AM, sagar pareek <[email protected]>wrote:
>
>> Well its not like that
>> first u have x=3;
>> now u have to do
>> y=++x + ++x + ++X;
>> before doing first addition
>> y=(++x + ++x) + ++x;
>>        ^          ^
>>
>> above spotted x will increase , before their addition
>> and then
>> y= 5+5 + ++x;
>> now
>> y=10+ 6
>> y=16;
>>
>> hope u now get it :)
>>
>>
>> On Sun, Jul 24, 2011 at 2:30 PM, Arun Vishwanathan <
>> [email protected]> wrote:
>>
>>> *x= 3 initially
>>>
>>>
>>> On Sun, Jul 24, 2011 at 11:00 AM, Arun Vishwanathan <
>>> [email protected]> wrote:
>>>
>>>> if that is the case as u say, then wont it be 3+ 4+ 5 when x +3
>>>> initially?..and then x increments by one later due to the single post
>>>> increment
>>>>
>>>>
>>>> On Sun, Jul 24, 2011 at 10:15 AM, sagar pareek 
>>>> <[email protected]>wrote:
>>>>
>>>>> nope compiler read it from left to right
>>>>>
>>>>>
>>>>> On Sun, Jul 24, 2011 at 12:05 AM, Arun Vishwanathan <
>>>>> [email protected]> wrote:
>>>>>
>>>>>> @sagar: if what u said previously holds as in when u say y=x++ + ++x
>>>>>> is evaluated as 4+4 since ++x results in 4 and 4 is used in x++ too (cos
>>>>>> post increment increments x later) then for y=x++ + ++x + ++x with x
>>>>>> beginning as 3 shud the expression not be evaluated as 5+5+4( from rhs 
>>>>>> ++x
>>>>>> does a 3 to 4 and another ++x does 4 to 5 and 5 is used in x++) .later x
>>>>>> becomes 6 ?
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> On Sat, Jul 23, 2011 at 2:39 PM, sagar pareek 
>>>>>> <[email protected]>wrote:
>>>>>>
>>>>>>> sorry for above...typo mistake :-
>>>>>>>
>>>>>>>  yup
>>>>>>> but what about this
>>>>>>> x=3;
>>>>>>>  y= x++ + ++x + ++x; // it is executed as:-
>>>>>>>
>>>>>>> during first addition, increase the value of x, now first addition
>>>>>>> will be 4+4 + ++x;
>>>>>>> now for second addition it will be like
>>>>>>> 8+5
>>>>>>> hence final value of y=13;
>>>>>>> do it by urself
>>>>>>>
>>>>>>> On Sat, Jul 23, 2011 at 6:09 PM, sagar pareek <[email protected]
>>>>>>> > wrote:
>>>>>>>
>>>>>>>> yup
>>>>>>>> but what about this
>>>>>>>> x=4;
>>>>>>>> y= x++ + ++x + ++x; // it is executed as:-
>>>>>>>>
>>>>>>>> during first addition, increase the value of x, now first addition
>>>>>>>> will be 4+4 + ++x;
>>>>>>>> now for second addition it will be like
>>>>>>>> 8+5
>>>>>>>> hence final value of y=13;
>>>>>>>> do it by urself
>>>>>>>>
>>>>>>>> On Sat, Jul 23, 2011 at 2:54 PM, shady <[email protected]> wrote:
>>>>>>>>
>>>>>>>>> @sagar
>>>>>>>>> would it get evaluated like this ?
>>>>>>>>> supposing x = 3;
>>>>>>>>>
>>>>>>>>> y = x++ + ++x; becomes y = (x=x+1) + (x=x+1);
>>>>>>>>> then x=x+1;
>>>>>>>>>
>>>>>>>>> so x = 5, y = 8;
>>>>>>>>>
>>>>>>>>> On Sat, Jul 23, 2011 at 2:48 PM, sagar pareek <
>>>>>>>>> [email protected]> wrote:
>>>>>>>>>
>>>>>>>>>> @Venga
>>>>>>>>>> if u are doing this
>>>>>>>>>> y= x++ + ++x; //x=3
>>>>>>>>>> then it would be
>>>>>>>>>> like that :-
>>>>>>>>>> ++x; //x=4
>>>>>>>>>> y=x+x;
>>>>>>>>>> x++;
>>>>>>>>>>
>>>>>>>>>> i thing this is sufficient  :)
>>>>>>>>>>
>>>>>>>>>> On Sat, Jul 23, 2011 at 1:20 PM, Interstellar Overdrive <
>>>>>>>>>> [email protected]> wrote:
>>>>>>>>>>
>>>>>>>>>>> The expression y = x++ + x++ + ++y;  is not a valid one. The
>>>>>>>>>>> result is compiler dependent
>>>>>>>>>>> Read this for reference :http://c-faq.com/expr/seqpoints.html
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> --
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>>>>>>>>>>>
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>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> --
>>>>>>>>>> **Regards
>>>>>>>>>> SAGAR PAREEK
>>>>>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>>>>>> NIT ALLAHABAD
>>>>>>>>>>
>>>>>>>>>> --
>>>>>>>>>> You received this message because you are subscribed to the Google
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>>>>>>>>
>>>>>>>>
>>>>>>>> --
>>>>>>>> **Regards
>>>>>>>> SAGAR PAREEK
>>>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>>>> NIT ALLAHABAD
>>>>>>>>
>>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> --
>>>>>>> **Regards
>>>>>>> SAGAR PAREEK
>>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>>> NIT ALLAHABAD
>>>>>>>
>>>>>>>   --
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>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>>>  Arun Vish
>>>>>> Graduate Student
>>>>>> Department of Computer Science
>>>>>> University of Southern California
>>>>>>
>>>>>> --
>>>>>> You received this message because you are subscribed to the Google
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>>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> **Regards
>>>>> SAGAR PAREEK
>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>> NIT ALLAHABAD
>>>>>
>>>>> --
>>>>> You received this message because you are subscribed to the Google
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>>>>>
>>>>
>>>>
>>>>
>>>> --
>>>>  Arun Vish
>>>> Graduate Student
>>>> Department of Computer Science
>>>> University of Southern California
>>>>
>>>>
>>>
>>>
>>> --
>>>  Arun Vish
>>> Graduate Student
>>> Department of Computer Science
>>> University of Southern California
>>>
>>> --
>>> You received this message because you are subscribed to the Google Groups
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>>
>>
>>
>> --
>> **Regards
>> SAGAR PAREEK
>> COMPUTER SCIENCE AND ENGINEERING
>> NIT ALLAHABAD
>>
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>
>
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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