*x= 3 initially

On Sun, Jul 24, 2011 at 11:00 AM, Arun Vishwanathan
<[email protected]>wrote:

> if that is the case as u say, then wont it be 3+ 4+ 5 when x +3
> initially?..and then x increments by one later due to the single post
> increment
>
>
> On Sun, Jul 24, 2011 at 10:15 AM, sagar pareek <[email protected]>wrote:
>
>> nope compiler read it from left to right
>>
>>
>> On Sun, Jul 24, 2011 at 12:05 AM, Arun Vishwanathan <
>> [email protected]> wrote:
>>
>>> @sagar: if what u said previously holds as in when u say y=x++ + ++x is
>>> evaluated as 4+4 since ++x results in 4 and 4 is used in x++ too (cos post
>>> increment increments x later) then for y=x++ + ++x + ++x with x beginning as
>>> 3 shud the expression not be evaluated as 5+5+4( from rhs ++x does a 3 to 4
>>> and another ++x does 4 to 5 and 5 is used in x++) .later x becomes 6 ?
>>>
>>>
>>>
>>>
>>> On Sat, Jul 23, 2011 at 2:39 PM, sagar pareek <[email protected]>wrote:
>>>
>>>> sorry for above...typo mistake :-
>>>>
>>>> yup
>>>> but what about this
>>>> x=3;
>>>>  y= x++ + ++x + ++x; // it is executed as:-
>>>>
>>>> during first addition, increase the value of x, now first addition will
>>>> be 4+4 + ++x;
>>>> now for second addition it will be like
>>>> 8+5
>>>> hence final value of y=13;
>>>> do it by urself
>>>>
>>>> On Sat, Jul 23, 2011 at 6:09 PM, sagar pareek <[email protected]>wrote:
>>>>
>>>>> yup
>>>>> but what about this
>>>>> x=4;
>>>>> y= x++ + ++x + ++x; // it is executed as:-
>>>>>
>>>>> during first addition, increase the value of x, now first addition will
>>>>> be 4+4 + ++x;
>>>>> now for second addition it will be like
>>>>> 8+5
>>>>> hence final value of y=13;
>>>>> do it by urself
>>>>>
>>>>> On Sat, Jul 23, 2011 at 2:54 PM, shady <[email protected]> wrote:
>>>>>
>>>>>> @sagar
>>>>>> would it get evaluated like this ?
>>>>>> supposing x = 3;
>>>>>>
>>>>>> y = x++ + ++x; becomes y = (x=x+1) + (x=x+1);
>>>>>> then x=x+1;
>>>>>>
>>>>>> so x = 5, y = 8;
>>>>>>
>>>>>> On Sat, Jul 23, 2011 at 2:48 PM, sagar pareek 
>>>>>> <[email protected]>wrote:
>>>>>>
>>>>>>> @Venga
>>>>>>> if u are doing this
>>>>>>> y= x++ + ++x; //x=3
>>>>>>> then it would be
>>>>>>> like that :-
>>>>>>> ++x; //x=4
>>>>>>> y=x+x;
>>>>>>> x++;
>>>>>>>
>>>>>>> i thing this is sufficient  :)
>>>>>>>
>>>>>>> On Sat, Jul 23, 2011 at 1:20 PM, Interstellar Overdrive <
>>>>>>> [email protected]> wrote:
>>>>>>>
>>>>>>>> The expression y = x++ + x++ + ++y;  is not a valid one. The result
>>>>>>>> is compiler dependent
>>>>>>>> Read this for reference :http://c-faq.com/expr/seqpoints.html
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>>
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>>>>>>>
>>>>>>> --
>>>>>>> **Regards
>>>>>>> SAGAR PAREEK
>>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>>> NIT ALLAHABAD
>>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> **Regards
>>>>> SAGAR PAREEK
>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>> NIT ALLAHABAD
>>>>>
>>>>>
>>>>
>>>>
>>>> --
>>>> **Regards
>>>> SAGAR PAREEK
>>>> COMPUTER SCIENCE AND ENGINEERING
>>>> NIT ALLAHABAD
>>>>
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>>>
>>>
>>>
>>> --
>>> Arun Vish
>>> Graduate Student
>>> Department of Computer Science
>>> University of Southern California
>>>
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>>
>>
>>
>> --
>> **Regards
>> SAGAR PAREEK
>> COMPUTER SCIENCE AND ENGINEERING
>> NIT ALLAHABAD
>>
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>
>
>
> --
> Arun Vish
> Graduate Student
> Department of Computer Science
> University of Southern California
>
>


-- 
Arun Vish
Graduate Student
Department of Computer Science
University of Southern California

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