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------- Additional comments from [EMAIL PROTECTED] Wed Jan 11 12:38:19 -0800 2006 ------- I would like to add the following info: I checked the behaviour in OOo 1.1.5 and OOo 2.0.1 and found the following: If the character immediately left of the current cursor position is a space, you will not be able to type in another one. BUT: If the character to the left of the cursor is a nonspace character, and the next character to the right of the cursor is already a space, you will still be able to type in another one and end up with two (or more) spaces. However it appears that detection generally works only for consecutively typed characters as for example you will get the same result if you type a "/2" and then go back to add a "1" so that it results in "1/2". It will not be replaced, but if you directly type "1/2" it will be. --------------------------------------------------------------------- Please do not reply to this automatically generated notification from Issue Tracker. Please log onto the website and enter your comments. http://qa.openoffice.org/issue_handling/project_issues.html#notification --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
