I suspect the trickiest part of specifying raw string literals will be
the lexer's modal behavior for Unicode escapes. As such, I am going to
put the behavior under the microscope. Here is what the JEP has to say:
Unicode escapes, in the form \uxxxx, are processed as part of character
input prior to interpretation by the lexer. To support the raw string
literal as-is requirement, Unicode escape processing is disabled when
the lexer encounters an opening backtick and reenabled when encountering
a closing backtick.
I would like to assume that if the lexer comes across the six tokens \ u
0 0 6 0 then it should interpret them as a Unicode escape representing
a backtick _and then continue as if consuming the tokens of a raw string
literal_. However, the mention of _an_ opening backtick and _a_ closing
backtick gave me pause, given that repeated backticks can serve as the
opening delimiter and the closing delimiter. For absolute clarity, let's
write out examples to confirm intent: (Jim, please confirm or deny as
you see fit!)
1. String s = \u0060`;
Illegal. The RHS is lexed as ``; which is disallowed by the grammar.
2. String s = \u0060Hello\u0060;
Illegal. The RHS is lexed as `Hello\u0060; and so on for the rest of
the compilation unit -- the six tokens \ u 0 0 6 0 are not treated as a
Unicode escape since we're lexing a raw string literal. And without a
closing delimiter before the end of the compilation unit, a compile-time
3a. String s = \u0060Hello`;
Legal. The RHS is lexed as `Hello`; which is well formed.
3b. String s = \u0060\u0060Hello`;
Depends! If you take the JEP literally, then just the Unicode escape
which serves as the first opening backtick ("_an_ opening backtick") is
enough to enter raw-string mode. That makes the code legal: the RHS is
lexed as `\u0060Hello`; which is well formed. On the other hand, you
might think that we shouldn't enter raw-string mode until the lexer in
traditional mode has lexed the opening delimiter fully (i.e. ALL the
opening backticks). Then, the code in 3b is illegal, because the opening
delimiter (``) and the closing delimiter (`) are not symmetric.
I think we should take the JEP literally, so that 3b is legal. And then,
some more examples:
4a. String s = \u0060`Hello``;
Legal. The RHS is lexed as ``Hello``; which is well formed.
4b. String s = \u0060\u0060Hello``;
Illegal. The RHS is lexed as `\u0060Hello``; which is disallowed by
the grammar. A raw string literal containing 11 tokens is immediately
followed by a ` token and a ; token which are not expected.
4c. String s = \u0060\u0060Hello`\u0060;
Depends! If you take the JEP literally, where _a_ closing backtick is
enough to re-enable Unicode escape processing, then the RHS is lexed as
`\u0060Hello``; which is illegal per 4b. On the other hand, if you
think that we shouldn't re-enter traditional mode until the lexer in
raw-string mode has lexed the closing delimiter fully (i.e. ALL the
closing backticks), then presumably you think analogously about the
opening delimiter, so the RHS would be lexed as ``Hello`\u0060; which
is illegal per 2 (no closing delimiter `` before the end of the
5. String s = \u0060`Hello`\u0060;
I put this here because it looks nice. It hits the same issues as 3b and 4c.