nah. first, he said that the endpoint wants GET params, and you are
opening with POST method below. you don't need to write data to the
stream. the data is passed to the endpoint as GET params.
if you just want to pass the get params, it's enough to just call
openConnection(). depending on how the endpoint returns a response, you
can check the response code with getResponseCode(), or you can read a
data response (XML, JSON, etc) by calling getInputStream(). here's the
simplest case,
URL url = "" URL(urlString);
HttpURLConnection uc = (HttpURLConnection)
url.openConnection();
uc.setReadTimeout(30 * 1000); // 30 seconds
if (uc.getResponseCode() != 200) {
//TODO: handle error and return
}
reader = new BufferedReader(new
InputStreamReader(uc.getInputStream(), "ISO-8859-1"), 8192);
while ((line = reader.readLine()) != null) {
result.append(line);
result.append('\n');
}
// result data is in "result"
On 9/27/09 11:07 AM, Alok Kulkarni wrote:
This works
URL url = "" URL(serverURL);
// open the conncetion
HttpURLConnection connection =
(HttpURLConnection)url.openConnection();
// Let the run-time system (RTS) know that we want
input.
connection.setDoInput(true);
// Let the RTS know that we want to do output
connection.setDoOutput(true);
// No caching, we want the real thing
connection.setUseCaches(false);
// set the content type property
connection.setRequestProperty("Content-type",strContenttype);
// set request method
connection.setRequestMethod("POST");
// create the post body to send
String content = credDevPair.toString();
Log.i("Request ====....... ",content);
DataOutputStream printout = new DataOutputStream (
connection.getOutputStream () );
// send the data
printout.writeBytes(content);
printout.flush();
printout.close();
On Sun, Sep 27, 2009 at 11:25 PM, HTN <[email protected]>
wrote:
It's through GET parameters. I can type in the following command in a
browser's URL box and it works:
http://192.168.0.12/output_format=xml&DeviceNum=13&action="">
I'm used to sending commands through TCP sockets so I'm sure what's
the best way to send a URL command. I'm guessing the "opening" a URL
part isn't adequate.
On Sep 26, 8:49 pm, Jeffrey Blattman <[email protected]>
wrote:
> you are opening a URL, then writing that URL
to the stream you open at
> the URL. that's probably not what you wanted. what's the URL, and
what
> is the "command" you are trying to pass? how does the endpoint
accept
> the command? by reading POST data? through GET parameters?
>
> On 9/25/09 7:31 PM, HTN wrote:
>
>
>
>
>
> > I'm developing a remote app that sends commands via http.
Normally I
> > type in a link in a browser and the command will work. With
Android, I
> > would like it to work with a press of a button. I tried the
following
> > code and it didn’t work:
>
> > URL url = "" URL(urlString);
>
> > URLConnection connection = url.openConnection();
> > connection.setDoOutput(true);
>
> > OutputStreamWriter out = new OutputStreamWriter
> > (connection.getOutputStream());
> > out.write(urlString);
> > out.close();
>
> > "urlstring" is the http command link.
>
> > Any ideas? Am I on the wrong track? I'm confused because
technically I
> > don't need to write anything to the link. I would think it
would work
> > if I just open the connection.
>
> > Thanks.
>
> --
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