Oh, ok.. I thought instead of POST he can use get there. but thanks for the
advice :)

On Mon, Sep 28, 2009 at 12:16 AM, Jeffrey Blattman <
[email protected]> wrote:

>  no, there's a default read timeout. the only thing i noticed wrong was
> that you were writing to URL itself to the stream.
>
>
> On 9/27/09 11:42 AM, HTN wrote:
>
> Seems like I was on the right track as I had url.openconnection. Is
> the ReadTimout portion what I was doing wrong?
>
> I'll try the code out when I get back home tomorrow. Thanks for the
> help.
>
>
> On Sep 27, 2:21 pm, Jeffrey Blattman <[email protected]> 
> <[email protected]>
> wrote:
>
>
>  nah. first, he said that the endpoint wants GET params, and you are
> opening with POST method below. you don't need to write data to the
> stream. the data is passed to the endpoint as GET params.
>
> if you just want to pass the get params, it's enough to just call
> openConnection(). depending on how the endpoint returns a response, you
> can check the response code with getResponseCode(), or you can read a
> data response (XML, JSON, etc) by calling getInputStream(). here's the
> simplest case,
>
>              URL url = new URL(urlString);
>              HttpURLConnection uc = (HttpURLConnection)
> url.openConnection();
>              uc.setReadTimeout(30 * 1000); // 30 seconds
>
>              if (uc.getResponseCode() != 200) {
>                  //TODO: handle error and return
>              }
>
>              reader = new BufferedReader(new
> InputStreamReader(uc.getInputStream(), "ISO-8859-1"), 8192);
>              while ((line = reader.readLine()) != null) {
>                  result.append(line);
>                  result.append('\n');
>              }
>
>              // result data is in "result"
>
> On 9/27/09 11:07 AM, Alok Kulkarni wrote:
>
>
>
>
>
>
>
>  This works
> URL url = new URL(serverURL);
>
>
>                   // open the conncetion
>             HttpURLConnection connection =
> (HttpURLConnection)url.openConnection();
>
>
>                   // Let the run-time system (RTS) know that we want input.
>             connection.setDoInput(true);
>             // Let the RTS know that we want to do output
>             connection.setDoOutput(true);
>             // No caching, we want the real thing
>             connection.setUseCaches(false);
>             // set the content type property
>             connection.setRequestProperty("Content-type",strContenttype);
>
>
>                   // set request method
>             connection.setRequestMethod("POST");
>             // create the post body to send
>             String content = credDevPair.toString();
>             Log.i("Request ====....... ",content);
>             DataOutputStream printout = new DataOutputStream (
> connection.getOutputStream () );
>
>
>                   // send the data
>             printout.writeBytes(content);
>             printout.flush();
>             printout.close();
>
>
>       On Sun, Sep 27, 2009 at 11:25 PM, HTN 
> <[email protected]<mailto:[email protected]> <[email protected]>> wrote:
>
>
>           It's through GET parameters. I can type in the following command in 
> a
>     browser's URL box and it works:
>    http://192.168.0.12/output_format=xml&DeviceNum=13&action=SetTarget&n...
>     
> <http://192.168.0.12/output_format=xml&DeviceNum=13&action=SetTarget&n...> 
> <http://192.168.0.12/output_format=xml&DeviceNum=13&action=SetTarget&n...>
>
>           I'm used to sending commands through TCP sockets so I'm sure what's
>     the best way to send a URL command. I'm guessing the "opening" a URL
>     part isn't adequate.
>
>
>           On Sep 26, 8:49 pm, Jeffrey Blattman <[email protected]
>     <mailto:[email protected]> <[email protected]>>
>     wrote:
>     > you are opening a URL, then writing that URL to the stream you
>     open at
>     > the URL. that's probably not what you wanted. what's the URL,
>     and what
>     > is the "command" you are trying to pass? how does the endpoint
>     accept
>     > the command? by reading POST data? through GET parameters?
>
>
>           > On 9/25/09 7:31 PM, HTN wrote:
>
>
>           > > I'm developing a remote app that sends commands via http.
>     Normally I
>     > > type in a link in a browser and the command will work. With
>     Android, I
>     > > would like it to work with a press of a button. I tried the
>     following
>     > > code and it didn’t work:
>
>
>           > >             URL url = new URL(urlString);
>
>
>           > >              URLConnection connection = url.openConnection();
>     > >              connection.setDoOutput(true);
>
>
>           > >              OutputStreamWriter out = new OutputStreamWriter
>     > > (connection.getOutputStream());
>     > >            out.write(urlString);
>     > >            out.close();
>
>
>           > > "urlstring" is the http command link.
>
>
>           > > Any ideas? Am I on the wrong track? I'm confused because
>     technically I
>     > > don't need to write anything to the link. I would think it
>     would work
>     > > if I just open the connection.
>
>
>           > > Thanks.
>
>
>           > --
>
>
>  --
>
>
>  >
>
>
>
> --
>

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