Don't put it in the xml/ directory. That does indeed get compiled into a binary format, and you'd need to use the corresponding API for reading it.
(Or you could recode to use that API, and gain efficiency and space -- but first, you'd like to test the code you've already written, right?) So put your test.xml into the raw/ directory instead of the xml/ directory (and use R.raw.test). More info here: http://developer.android.com/intl/de/guide/topics/resources/providing-resources.html And if you want to move it back and get the benefits of using the compiled format, you'll access it starting with this API: http://developer.android.com/intl/de/reference/android/content/res/Resources.html#getXml(int) On Jun 30, 12:36 pm, "RespeckKnuckles (John Licato)" <respeckknuckl...@gmail.com> wrote: > Hey guys, > > I have some xml files with a custom format (based on the scxml > specifications) that I want my program to read. I've already written > the code to read it, but I'm running into problems actually reading > the file itself. I want the file to be compiled with the apk, as it > will not be changed at all during run time. So I put the file > (test.xml) in the res/xml/ folder, and got the inputstream by using: > > getResources().openRawResource(R.xml.test); > > but when I read in this inputstream it is complete jibberish, which > makes me suspect it is being read in binary, as openRawResource() is > often used for binary files like images, if I am correct. What is the > correct way to do this? -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
