That's a good thing to do, but he'll have to rewrite his code. It would be wise to test that his existing code is working as a baseline, and check it in to revision control, and write a few unit tests, before doing that.
Unless his code is trivial, of course. Or his head gets too bloody from pounding his head against a brick wall... On Jul 1, 12:04 pm, Mark Murphy <[email protected]> wrote: > Put it back in res/xml/. Use getResources().getXml() to get an > XmlPullParser on the file. > > On Thu, Jul 1, 2010 at 2:47 PM, RespeckKnuckles (John Licato) > > > > > > <[email protected]> wrote: > > Just in case the <?xml ?> element was the problem, I tried this xml > > code instead: > > > <?xml version="1.0" encoding="utf-8"?> > > <HTML></HTML> > > > and still didn't work. > > > On Jul 1, 12:46 pm, "RespeckKnuckles (John Licato)" > > <[email protected]> wrote: > >> Hey guys, > > >> I put the xml file into the res/raw directory and it works better, but > >> still not working completely. Here is the code I'm using: > > >> InputStream toParse = > >> getResources().openRawResource(R.raw.test); // > >> file is in res/raw/test.xml > >> DocumentBuilder db = > >> > >> DocumentBuilderFactory.newInstance().newDocumentBuilder(); > >> Document d = db.parse(toParse); > >> Element rootElement = d.getDocumentElement(); > > >> It fails at db.parse(), saying "Unexpected end of document found." > >> I've converted the toParse stream into a string and verified it is > >> correct, and I simplified it so that the only xml it reads is: > > >> <HTML></HTML> > > >> and it still says the same thing. This may be more of a java DOM > >> issue, but do any of you have any ideas? > > >> On Jul 1, 1:42 am, piyu <[email protected]> wrote: > > >> > Hi John, > > >> > Can copy here code to know how you are reading fron input stream. > > >> > Thanks in advance. > > >> > On Jul 1, 12:36 am, "RespeckKnuckles(John Licato)" > > >> > <[email protected]> wrote: > >> > > Hey guys, > > >> > > I have some xml files with a custom format (based on the scxml > >> > > specifications) that I want my program to read. I've already written > >> > > the code to read it, but I'm running into problems actually reading > >> > > the file itself. I want the file to be compiled with the apk, as it > >> > > will not be changed at all during run time. So I put the file > >> > > (test.xml) in the res/xml/ folder, and got the inputstream by using: > > >> > > getResources().openRawResource(R.xml.test); > > >> > > but when I read in this inputstream it is complete jibberish, which > >> > > makes me suspect it is being read in binary, as openRawResource() is > >> > > often used for binary files like images, if I am correct. What is the > >> > > correct way to do this? > > > -- > > You received this message because you are subscribed to the Google > > Groups "Android Developers" group. > > To post to this group, send email to [email protected] > > To unsubscribe from this group, send email to > > [email protected] > > For more options, visit this group at > >http://groups.google.com/group/android-developers?hl=en > > -- > Mark Murphy (a Commons > Guy)http://commonsware.com|http://github.com/commonsguyhttp://commonsware.com/blog|http://twitter.com/commonsguy > > Android Training...At Your Office:http://commonsware.com/training -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
