No idea off the top of my head, other than that something you think is true probably isn't. Not exactly a helpful observation...
But why not try <HTML/> instead of <HTML></HTML>, and verify that you're getting that. They're equivalent, but going to even simpler XML may lead you to discover the problem by getting you to go through things again. Make sure you didn't accidentally leave in the code to read from the stream and print it out! Also, make sure your input file is in utf-8. (Which in this case, is the same as ASCII/IS0-646). You may have used some editing tool that put it in UTF-16. Or perhaps there's a byte-order mark inserted, and perhaps the parser doesn't handle that properly. On Jul 1, 10:46 am, "RespeckKnuckles (John Licato)" <respeckknuckl...@gmail.com> wrote: > Hey guys, > > I put the xml file into the res/raw directory and it works better, but > still not working completely. Here is the code I'm using: > > InputStream toParse = > getResources().openRawResource(R.raw.test); // > file is in res/raw/test.xml > DocumentBuilder db = > > DocumentBuilderFactory.newInstance().newDocumentBuilder(); > Document d = db.parse(toParse); > Element rootElement = d.getDocumentElement(); > > It fails at db.parse(), saying "Unexpected end of document found." > I've converted the toParse stream into a string and verified it is > correct, and I simplified it so that the only xml it reads is: > > <HTML></HTML> > > and it still says the same thing. This may be more of a java DOM > issue, but do any of you have any ideas? > > On Jul 1, 1:42 am, piyu <spk2p...@gmail.com> wrote: > > > > > Hi John, > > > Can copy here code to know how you are reading fron input stream. > > > Thanks in advance. > > > On Jul 1, 12:36 am, "RespeckKnuckles(John Licato)" > > > <respeckknuckl...@gmail.com> wrote: > > > Hey guys, > > > > I have some xml files with a custom format (based on the scxml > > > specifications) that I want my program to read. I've already written > > > the code to read it, but I'm running into problems actually reading > > > the file itself. I want the file to be compiled with the apk, as it > > > will not be changed at all during run time. So I put the file > > > (test.xml) in the res/xml/ folder, and got the inputstream by using: > > > > getResources().openRawResource(R.xml.test); > > > > but when I read in this inputstream it is complete jibberish, which > > > makes me suspect it is being read in binary, as openRawResource() is > > > often used for binary files like images, if I am correct. What is the > > > correct way to do this? -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
