Great! the answer is really helpful for me. Thanks a lot. BTW, it would be better if there are clear explain of android api document.
On Nov 4, 12:14 am, Mike Reed <[EMAIL PROTECTED]> wrote: > canvas.drawBitmap(bitmap, matrix, ...) > > This is really just a more efficient way to do... > > canvas.save(Canvas.MATRIX_SAVE_FLAG); > canvas.concat(matrix); > drawBitmap(bitmap, 0, 0, ...); > canvas.restore(); > > In the original example, the matrix had a -1 scale in X. This means > that all X coordinates will be negated. Thus the image will draw > flipped in X, but it will also appear to the left of the Y axis, which > defaults to the left edge of the view. Thus the fix was to post- > translate everything to the right by at least the width of the bitmap, > to make it appear on screen. > > Another fix could have been > > matrix.setScale(-1, 1); > matrix.postTranslate(bitmap.getWidth(), 0); > canvas.drawBitmap(bitmap, matrix, ...); > > mike > > On Nov 3, 2008, at 10:46 AM, Guolong wrote: > > thanks, it do work. > > On Nov 3, 1:44 pm, Romain Guy <[EMAIL PROTECTED]> wrote: > > > sprite = > > BitmapFactory > > .decodeResource(appContext.getResources(),R.drawable.spritegfx); > > canvas.save(); > > canvas.scale(-1.0f, 1.0f); > > canvas.drawBitmap(sprite, 0,0, null); > > canvas.restore(); > > > This will work but you also need to translate the image too. You are > > just drawing it outside of the canvas. > > > On Sun, Nov 2, 2008 at 8:42 AM, Guolong <[EMAIL PROTECTED]> > > wrote: > > >> hello, > > >> I want to draw a fliped image and try following code: > > >> sprite = > >> BitmapFactory > >> .decodeResource(appContext.getResources(),R.drawable.spritegfx); > >> Matrix temp1=new Matrix(); > >> temp1.preScale(-1.0f,1.0f); > >> canvas.drawBitmap(sprite, temp1, null); > > >> But it does not work. neither work for the following code: > > >> sprite = > >> BitmapFactory > >> .decodeResource(appContext.getResources(),R.drawable.spritegfx); > >> canvas.save(); > >> canvas.scale(-1.0f, 1.0f); > >> canvas.drawBitmap(sprite, 0,0, null); > >> canvas.restore(); > > >> Any idea for this problem please? > > >> Any way, following code do work. > >> sprite = > >> BitmapFactory > >> .decodeResource(appContext.getResources(),R.drawable.spritegfx); > >> Matrix temp1=new Matrix(); > >> temp1.preScale(-1.0f,1.0f); > >> flipedSprite = Bitmap.createBitmap(sprite , 0, 0, > >> sprite .getWidth(), > >> sprite .getHeight(), temp1, false); > >> canvas.drawBitmap(flipedSprite , 0,0, null); > > >> But I just don't want to create a new bitmap for every fliped image > >> because there're a lot of fliped or mirrored image in my program. > > > -- > > Romain Guywww.curious-creature.org --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -~----------~----~----~----~------~----~------~--~---
