You can also simply turn on the copy protection when you are publishing the App, Google keeps saying they are going to remove it "soon" though. It hopefully provides some annoyance to crackers.
Another potential issue with licensing service is that it requires an internet connection to authenticate and if you are too aggressive with the checking you can lock users out when they don't have internet. On Thursday, May 10, 2012 9:34:18 PM UTC+2, Doug Gordon wrote: > > Good information -- thanks all. My app is very specialized (genealogy) > and low volume, and I can usually count on my users being older and > more serious, and less likely to cheat than the kids that want to hack > the latest games. I was just wondering if there was any inherent > protection since it is definitely not worth my while to build anything > into the product. > > On May 8, 9:24 pm, John Coryat <[email protected]> wrote: > > I think the bottom line on app copy protection is: > > > > The end result isn't worth the effort. Better to accept some piracy than > > prevent valid users from using the app. > > > > As Tim mentioned, the "Freemium" model is probably the most secure. > > Everyone has implemented their upgrade system independently so it would > be > > tricky for a hacker to figure out exactly what it takes for a free app > to > > perform in premium mode. That makes freemium more secure than anything > > overt. Another consideration is virtually all of the top apps and games > use > > in-app purchases for revenue generation. There's a reason for that. You > > might want to look at using that for yourself as well. > > > > -John Coryat -- You received this message because you are subscribed to the Google Groups "Android Discuss" group. To view this discussion on the web visit https://groups.google.com/d/msg/android-discuss/-/loxZ2Z5VsrMJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/android-discuss?hl=en.
