There is an onSend or on_send method wich you could overwrite with your own
function, not sure it applies to the channel or pipe object
On Apr 8, 2013 3:02 PM, "Nicolas Guibert" <[email protected]>
wrote:
> Hi Pablo,
>
> On the client side, I have just added a "listener" like this in core.js:
> parseResponse: function(raws, callback)
> {
> if(typeof window.console != 'undefined'
> && typeof window.console.log != 'undefined')
> {
> console.log("OOOOOOOOO RAW core_new2.js: parseResponse
> raws:"+raws +" callback:"+callback);
> }
>
> On the server side, I use this syntax to send a new message:
> pipe_player.sendRaw(raw_name,raw_details);
>
> This said, I think that there is a good chance that I found my problem.
> When a message had gone wrong, I stored it with the pipe_player
> information. Although, I was properly cloning the message content to
> prevent it from being overriden in the meantime, I forgot to do the same
> with pipe_player. I will now store the pubid instead of pipe_player.
> Hopefully, this will be enough to solve a bug that has been in my code for
> one year and that was giving me much headache.
>
> Thanks for your interest Pablo. If you know a way to listen to what's
> coming out of the server, I am still interested as this can be helpful at
> any time.
>
> Nicolas.
>
>
>
>
>
> 2013/4/8 Pablo Tejada <[email protected]>
>
>> Can you post some code of how you are sending the raw from ther server
>> and how you are listening for the raw on the client? Please do include how
>> you get the pipe object on where you send the raw through.
>> On Apr 8, 2013 9:05 AM, "Nicolas" <[email protected]> wrote:
>>
>>> Hi,
>>>
>>> I have run into an issue. The server most likely does not send some
>>> customs raws that he is supposed to send. Because these messages are not
>>> acknowledged by the client, the server tries to send them back again and
>>> again but the client never gets them.
>>>
>>> There are two possibilities here: either the server does not send the
>>> message or the client can't receive it. The connexion between the server
>>> and the client is not broken, because a third message is well received by
>>> the client.
>>>
>>> I'd like to log what actually comes out of the server. I guess the only
>>> way to do this is by tweaking the C code. Where is that? I can then
>>> recompile the code and see.
>>>
>>> Thanks for you help.
>>>
>>> Nicolas.
>>>
>>>
>>>
>>>
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>
>
>
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>
> Nicolas Guibert
>
> Games in Mind Ltd
>
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