Stephane Chazelas <stephane.chaze...@gmail.com> wrote:
> 2018-08-14 03:45:29 -0400, Shware Systems:
> > By XCU 2.9.2 Exit Status, the ! is right associative and all
> > shells should return 1 for "! break" in any context that
> > permits a pipeline; even if the pipe only has one element and
> > no "|" involved. I don't see that there's any ambiguity; while
> > special, break is still considered a command, not a keyword
> > like while or do.
> [...]
>
> But "break" is meant to break out of the loop. One can argue
> that it may happen *before* and preempts the shell retrieving
> its exit status and apply ! on it.
break is a command that has an exit code that is the previous saved exit code
and that has the side effect of leaving the loop.
The ! statement negates the current saved exit code and makes it the new saved
exit code.
> Same applies for "! exit 0" or "! return 0". Should that return
> with a 0 or 1 exit status? AFAICT, all shells return with 0 for
> "exit", but ash-based shells and zsh return with 1 for "return".
>
> See also:
>
> $ mksh -c 'for i in 1 2; do echo "$?"; (exit 3); continue; done'
> 0
> 3
I expect
0
0
> $ mksh -c 'for i in 1 2; do echo "$?"; ! continue; done'
> 0
> 0
I expect
0
1
Jörg
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