On 3/17/06 at 12:01 AM, [EMAIL PROTECTED] (Jason Davies) wrote:
>>Find: ^(\d+)$
>>Replace: <div class="gal-mini"><a
>>href="img/temp_05_06/tfr-\1.jpg"><img class="gen-img"
>>src="img/temp_05_06/tfr-\1-th.jpg" /></a></div>
>>If the 'temp_05_06' bit changes, you could use a second captured
>>string on each line (tab seperated, or similar), so you have two
>>things changing each time.
>Hi Jospeh
>I don't really understand how this would work - care to elaborate,
>just for interest?
The \d part represents a single digit. Adding, the '+' changes this to be a
string of one or more digits. putting this with '(' and ')' causes the found
sequence of digits to be memorized for use in the replacement pattern. The '^'
represents the beginning of a line and the '$' represents the end of a line.
So, the entire pattern represents a line with just digits on it.
Since this is the first point where a '(' and ')' pair occur, it is represented
in the replacement pattern as /1. So, wherever you see the \1 in the
replacement pattern is where the string of digits is placed. It might be worth
noting since the entire matched pattern is used as a whole instead of \1 a '&'
could have been used in the replacement pattern.
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