Thanks a lot to everybody. That was exactly the approach I was looking
for. And thaaaanks a lot too to Bill for the detailed explanation of
the code. I've been tweaking and modifying it in BBEdit and I think I
understand it. In fact, I tried to replace not only the .jpg number
but also the directory (05_06) and I could do it (man, grep is
powerful...) thanks to all your help.
Did I say thanks? :)
Cheers,
Arturo
On 17/03/06, Bill Rowe <[EMAIL PROTECTED]> wrote:
> On 3/17/06 at 12:01 AM, [EMAIL PROTECTED] (Jason Davies) wrote:
>
> >>Find: ^(\d+)$
>
> >>Replace: <div class="gal-mini"><a
> >>href="img/temp_05_06/tfr-\1.jpg"><img class="gen-img"
> >>src="img/temp_05_06/tfr-\1-th.jpg" /></a></div>
>
> >>If the 'temp_05_06' bit changes, you could use a second captured
> >>string on each line (tab seperated, or similar), so you have two
> >>things changing each time.
>
> >Hi Jospeh
>
> >I don't really understand how this would work - care to elaborate,
> >just for interest?
>
> The \d part represents a single digit. Adding, the '+' changes this to be a
> string of one or more digits. putting this with '(' and ')' causes the found
> sequence of digits to be memorized for use in the replacement pattern. The
> '^' represents the beginning of a line and the '$' represents the end of a
> line. So, the entire pattern represents a line with just digits on it.
>
> Since this is the first point where a '(' and ')' pair occur, it is
> represented in the replacement pattern as /1. So, wherever you see the \1 in
> the replacement pattern is where the string of digits is placed. It might be
> worth noting since the entire matched pattern is used as a whole instead of
> \1 a '&' could have been used in the replacement pattern.
>
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