>
>>>Find: ^(\d+)$
>
>>>Replace: <div class="gal-mini"><a
>>>href="img/temp_05_06/tfr-\1.jpg"><img class="gen-img"
>>>src="img/temp_05_06/tfr-\1-th.jpg" /></a></div>
>
>The \d part represents a single digit. Adding, the '+' changes this to
>be a string of one or more digits. putting this with '(' and ')'
>causes the found sequence of digits to be memorized for use in the
>replacement pattern. The '^' represents the beginning of a line and
>the '$' represents the end of a line. So, the entire pattern
>represents a line with just digits on it.
>
>Since this is the first point where a '(' and ')' pair occur, it is
>represented in the replacement pattern as /1. So, wherever you see the
>\1 in the replacement pattern is where the string of digits is placed.
>It might be worth noting since the entire matched pattern is used as a
>whole instead of \1 a '&' could have been used in the replacement
>pattern.
thanks for that and apologies for asking in an unclear way: I can follow the
grep - it was the overall logic. I should have quoted differently, my bad. What
was the first step, the placeholder part?
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