> > in hopes of explaining what is being talked around is this. You want 5V > from 11V so there's 6V difference. Those linear regulators will give you > the 5V at some current level(let's say 1A for simplicity). So you get 5V at > 1A and that's 5Watts(5V*1A) but that 1A of current is also involved in that > 6V drop from 11V to get you 5V. The energy/power wasted in that 6V drop is > calculated by the current of your load( 1A ) times the drop( 6V ) which is > 6Watts in the example. > > This is why Gerald is correct in his statement that the linear regulator is wasteful since in the example you only need 5W and have 6W of waste so have a total energy cost of 11W. A better solution would be a DC->DC converter and you can get those on amazon with free shipping from china(if you can wait) for less than $10. The take the input power turn it into a AC signal which can then be chopped and reassembled into a lower voltage with little energy loss.
for example: http://www.amazon.com/gp/product/B008BHAOQO Doug -- For more options, visit http://beagleboard.org/discuss --- You received this message because you are subscribed to the Google Groups "BeagleBoard" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
