I dunno why I have to say this, but Alberto and his nek'd behind might complain:
There are an infinite number of vectors with a scalar of zero on a two dimensional plane, though there are only two vectors with a scalar of zero on a one dimensional line. So, to make the vector-cardinality proof valid [soc.history.what-if, "non-linear equations"], I have to add that counting all vectors with scalars of zero as one vector with a start at the origin, the vector-cardinality proof that differentiable functions have cardinality less than or equal to the cardinality of the set of complex numbers. Wtf do I have to mention the details? Even these statements might have holes in them regarding my proof. Mark _______________________________________________ http://www.mccmedia.com/mailman/listinfo/brin-l
