Alberto said: > It looked like nonsense because you are too Cartesian. > Maybe you should think in some Riemmanian space, where > the theorem of Pythagoras is no longer valid.
Nevertheless, a Riemannian space has a metric (by definition), and so we can still generate scalars from the inner products of vectors (as long as the vectors are elements of the same tangent space). Rich GSV Differential Geometry Is Fun _______________________________________________ http://www.mccmedia.com/mailman/listinfo/brin-l
