Mark wrote:
>
> I dunno why I have to say this, but Alberto and his
> nek'd behind might complain:
>
Let me see.
> There are an infinite number of vectors with a scalar of
> zero on a two dimensional plane, though there are only
> two vectors with a scalar of zero on a one dimensional
> line.
The number of sets of infinite vectors with one scalar zero
is also infinite, but a much bigger infinite
> So, to make the vector-cardinality proof valid
> [soc.history.what-if, "non-linear equations"],
Try to extend the proof to the space constructed by
taking the complex polynomials, using the metric that
comes from the linear product <p, q> = integral from
0 to 1 of p(x) q*(x) dx, and using Cauchy sequences
to generete a Hilbert Space.
> I have to add that counting all vectors with scalars
> of zero as one vector with a start at the origin,
> the vector-cardinality proof that differentiable
> functions have cardinality less than or equal to
> the cardinality of the set of complex numbers.
It's a transfinite set, right? Are you accepting
the Continuum Hypotheses, or are you using an
alternative? Just remember that 2^aleph-0 can't
be aleph-aleph-1, but can be almost any other
aleph.
> Wtf do I have to mention the details? Even these
> statements might have holes in them regarding my
> proof.
It depends on the topology of the space. If any set
of holes that cover the whole space has a finite
subset of holes that cover the whole space, you
prove that the space is Compact.
Alberto Monteiro
_______________________________________________
http://www.mccmedia.com/mailman/listinfo/brin-l
