On 2/14/07, Gopi Krishna Komanduri <[EMAIL PROTECTED]> wrote:
>
> Hi Frnds,
> Why overloaded operator won't work for derived calss when we
> supply
> operator overloading method in base class and also we derived using public.
> Can any
> one of you please suggest.
Can you supply code to demonstrate what you're trying to do? Your
explanation isn't too clear:
#include <iostream>
class base {
public:
void foo(){ std::cout << "base::foo()\n"; }
virtual void bar() { std::cout << "base::bar()\n"; }
};
class derived : public base {
public:
void foo(){ std::cout << "derived::foo()\n"; }
virtual void bar() { std::cout << "derived::bar()\n"; }
};
int main(){
base* b;
b = new derived;
b->foo(); // base::foo() expected - what you're seeing?
b->bar(); // derived::bar() expected - what you want?
return 0;
}
--
PJH
Aio, quantitas magna frumentorum est
