> prakaashganth d <[EMAIL PROTECTED]> wrote:
> > Hi People,
> >
> > I have a doubt in C program.
Sounds more like homework to me.
> > Suppose i have declared int i = 1234;
> >
> > If I want to print only 12 (first 2 digits) using
> > printf statement, please suggest how do i
> > implement it.
Rajath N R <[EMAIL PROTECTED]> wrote:
> ...
> main()
The use of implicit int is lazy, as is the lack of
include for <stdio.h> which is _required_ for the
correct use of the variadic function printf.
> {
> int i = 1234;
> char buff[256];
> snprintf(buff, 256, "%d", i);
Note that snprintf is (unfortunately), not a standard
function in C90. It is standard in C99, but the specs
aren't the same as the extension offered by some C90
implementations.
It is possible to predetermine a buffer size that will
always be sufficient, based on sizeof(int) and CHAR_BIT.
[Left as an exercise.]
> printf("%c%c\n", buff[0], buff[1]);
I suggest...
printf("%.2s\n", buff);
...to at least do something more sensible if i is
less than 10. Although if i less than zero, the
behaviour may not be what's desired.
> }
--
Peter
