Arp/Warp server?

JPK

On Thu, Apr 19, 2012 at 9:00 AM, Eleanor Dodson
<eleanor.dod...@york.ac.uk>wrote:

> Several possibilities.
>
> 1) Phaser is very prone to reject solutions because of packing clashes..
>  (PS How do you reset the packing limit in the current GUI?)
> Running chainsaw before you begin the search can help - it prunes out
> patches where the sequences don't match and gives a sensibly truncated
> search model.
>
> 2) There is only one molecule - does it pack reasonably or are there great
> holes in the map with suspicious density for a 2nd molecule?
>
> I would refine the molecule you have and rebuild if possible, then use
> that model to search again
> Eleanor Dodson
>
>
>
> On 19 April 2012 03:24, Ed Pozharski <epozh...@umaryland.edu> wrote:
>
>> 36% solvent sounds too low.  Most protein crystals are at ~50%.  On the
>> other hand, if you assume one molecule, your solvent content jumps to
>> 68% - not unheard of, but somewhat high for 1.7A resolution dataset.
>>
>> But you have a good MR solution, just try to refine/rebuild and see what
>> you have in the density.
>>
>> Is your protein a dimer by any chance?  Then you may have two dimers,
>> only one is formed by crystal symmetry.  Thus you'd have 1.5 molecules
>> in asu, which would result in solvent content of ~52% - just right.  If
>> that is the case, run MR with the monomer.
>>
>> Cheers,
>>
>> Ed.
>>
>> On Thu, 2012-04-19 at 02:26 +0100, Krithika Sundaram wrote:
>> > Hi all,
>> >
>> > I am working on an oxidoreductase and having some trouble during
>> molecular replacement.
>> >
>> > The resolution of the crystal is 1.7 A and the space group is I4122 (a
>> = b = 121.086, c =156.93 and alpha = beta = gamma = 90).
>> >
>> > The cell content analysis results  predicted two molecules in the
>> asymmetric unit and the solvent content as 36 %. The Matthew's coefficient
>> is 1.94. The Wilson plot also looks fine.
>> >
>> > However, after molecular replacement (using Phaser) the result just
>> gives me just a single molecule. ( RFZ = 8.5 TFZ =13.9 PAK = 0 LLG =189
>> TFZ=18.0 LLG = 642)
>> >
>> > Any suggestions how to solve this problem?
>> >
>> > Thanks in advance.
>> >
>>
>
>


-- 
*******************************************
Jacob Pearson Keller
Northwestern University
Medical Scientist Training Program
email: j-kell...@northwestern.edu
*******************************************

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