http://www.nature.com/nsmb/journal/v4/n4/abs/nsb0497-269.html
http://scripts.iucr.org/cgi-bin/paper?S0021889800018227
Just collect 360 sweep instead of 180 on a non-decaying crystal and see
Rmerge go up due to increase in multiplicity (and enough with redundancy
term - the extra data is not really *redundant*). Is your resolution
worse or better?
This has been argued over before. Rmerge has some value in comparing
two datasets collected in perfectly identical conditions to see which
crystal is better and it may predict to some extent what R-values you
might expect. Otherwise, it's unreliable.
Given that it's been 15 years since this was pointed out in no less than
Nature group magazine, and we still hear that Rmerge should decide
resolution cutoff, chances are increasingly slim that I will personally
see the dethroning of that other major oppressor, R-value.
On Fri, 2012-06-01 at 10:59 -0700, aaleshin wrote:
> Please excuse my ignorance, but I cannot understand why Rmerge is unreliable
> for estimation of the resolution?
> I mean, from a theoretical point of view, <1/sigma> is indeed a better
> criterion, but it is not obvious from a practical point of view.
>
> <1/sigma> depends on a method for sigma estimation, and so same data
> processed by different programs may have different <1/sigma>. Moreover,
> HKL2000 allows users to adjust sigmas manually. Rmerge estimates sigmas from
> differences between measurements of same structural factor, and hence is
> independent of our preferences. But, it also has a very important ability to
> validate consistency of the merged data. If my crystal changed during the
> data collection, or something went wrong with the diffractometer, Rmerge will
> show it immediately, but <1/sigma> will not.
>
> So, please explain why should we stop using Rmerge as a criterion of data
> resolution?
>
> Alex
> Sanford-Burnham Medical Research Institute
> 10901 North Torrey Pines Road
> La Jolla, California 92037
>
>
>
> On Jun 1, 2012, at 5:07 AM, Ian Tickle wrote:
>
> > On 1 June 2012 03:22, Edward A. Berry <ber...@upstate.edu> wrote:
> >> Leo will probably answer better than I can, but I would say I/SigI counts
> >> only
> >> the present reflection, so eliminating noise by anisotropic truncation
> >> should
> >> improve it, raising the average I/SigI in the last shell.
> >
> > We always include unmeasured reflections with I/sigma(I) = 0 in the
> > calculation of the mean I/sigma(I) (i.e. we divide the sum of
> > I/sigma(I) for measureds by the predicted total no of reflections incl
> > unmeasureds), since for unmeasureds I is (almost) completely unknown
> > and therefore sigma(I) is effectively infinite (or at least finite but
> > large since you do have some idea of what range I must fall in). A
> > shell with <I/sigma(I)> = 2 and 50% completeness clearly doesn't carry
> > the same information content as one with the same <I/sigma(I)> and
> > 100% complete; therefore IMO it's very misleading to quote
> > <I/sigma(I)> including only the measured reflections. This also means
> > we can use a single cut-off criterion (we use mean I/sigma(I) > 1),
> > and we don't need another arbitrary cut-off criterion for
> > completeness. As many others seem to be doing now, we don't use
> > Rmerge, Rpim etc as criteria to estimate resolution, they're just too
> > unreliable - Rmerge is indeed dead and buried!
> >
> > Actually a mean value of I/sigma(I) of 2 is highly statistically
> > significant, i.e. very unlikely to have arisen by chance variations,
> > and the significance threshold for the mean must be much closer to 1
> > than to 2. Taking an average always increases the statistical
> > significance, therefore it's not valid to compare an _average_ value
> > of I/sigma(I) = 2 with a _single_ value of I/sigma(I) = 3 (taking 3
> > sigma as the threshold of statistical significance of an individual
> > measurement): that's a case of "comparing apples with pears". In
> > other words in the outer shell you would need a lot of highly
> > significant individual values >> 3 to attain an overall average of 2
> > since the majority of individual values will be < 1.
> >
> >> F/sigF is expected to be better than I/sigI because dx^2 = 2Xdx,
> >> dx^2/x^2 = 2dx/x, dI/I = 2* dF/F (or approaches that in the limit . . .)
> >
> > That depends on what you mean by 'better': every metric must be
> > compared with a criterion appropriate to that metric. So if we are
> > comparing I/sigma(I) with a criterion value = 3, then we must compare
> > F/sigma(F) with criterion value = 6 ('in the limit' of zero I), in
> > which case the comparison is no 'better' (in terms of information
> > content) with I than with F: they are entirely equivalent. It's
> > meaningless to compare F/sigma(F) with the criterion value appropriate
> > to I/sigma(I): again that's "comparing apples and pears"!
> >
> > Cheers
> >
> > -- Ian
--
Edwin Pozharski, PhD, Assistant Professor
University of Maryland, Baltimore
----------------------------------------------
When the Way is forgotten duty and justice appear;
Then knowledge and wisdom are born along with hypocrisy.
When harmonious relationships dissolve then respect and devotion arise;
When a nation falls to chaos then loyalty and patriotism are born.
------------------------------ / Lao Tse /
