Since Phil is no doubt in bed, I'll answer the easier part.  Your
second matrix is nearly the equivalent position (x,-y,-z).  This
is a two-fold rotation about the x axis.  You also have a translation
of about 31 A along x so if your A cell edge is about 62 A you have
a 2_1 screw.

Dale Tronrud

On 10/15/2013 12:29 PM, Yarrow Madrona wrote:
> Hi Phil,
> 
> Thanks for your help.
> 
> I ran a "Find-NCS" routine in the phenix package. It came up with what I
> pasted below:
> I am assuming the the first rotation matrix is just the identity. I need
> to read more to understand rotation matrices but I think the second one
> should have only a single -1 to account for a possible perfect 2(1) screw
> axis between the two subunits in the P21 asymetric unit. I am not sure why
> there are two -1 values. I may be way off in my interpretation in which
> case I will go read some more. I will also try what you suggested. Thanks.
> 
> -Yarrow
> 
> NCS operator using PDB
> 
> #1 new_operator
> rota_matrix    1.0000    0.0000    0.0000
> rota_matrix    0.0000    1.0000    0.0000
> rota_matrix    0.0000    0.0000    1.0000
> tran_orth     0.0000    0.0000    0.0000
> 
> center_orth   17.7201    1.4604   71.4860
> RMSD = 0
> (Is this the identity?)
> 
> #2 new_operator
> 
> rota_matrix    0.9994   -0.0259    0.0250
> rota_matrix   -0.0260   -0.9997    0.0018
> rota_matrix    0.0249   -0.0025   -0.9997
> tran_orth   -30.8649  -11.9694  166.9271
>> Hello Yarrow,
>>
>> Since you have a refined molecular replacement solution I recommend
>> using that rather than global intensity statistics.
>>
>> Obviously if you solve in P21 and it's really P212121 you should have
>> twice the number of molecules in the asymmetric unit and one half of the
>> P21 asymmetric unit should be identical to the other half.
>>
>> Since you've got decent resolution I think you can determine the real
>> situation for yourself: one approach would be to test to see if you can
>> symmetrize the P21 asymmetric unit so that the two halves are identical.
>>   You could do this via stiff NCS restraints (cartesian would be better
>> than dihedral).  After all the relative XYZs and even B-factors would be
>> more or less identical if you've rescaled a P212121 crystal form in P21.
>>   If something violates the NCS than it can't really be P212121.
>>
>> Alternatively you can look for clear/obvious symmetry breaking between
>> the two halves: different side-chain rotamers for surface side-chains
>> for example.  If you've got an ordered, systematic, difference in
>> electron density between the two halves of the asymmetric unit in P21
>> then that's a basis for describing it as P21 rather than P212121.
>> However if the two halves look nearly identical, down to equivalent
>> water molecule densities, then you've got no experimental evidence that
>> P21 with 2x molecules generates a better model than P212121 than 1x
>> molecules.  An averaging program would show very high correlation
>> between the two halves of the P21 asymmetric unit if it was really
>> P212121 and you could overlap the maps corresponding to the different
>> monomers using those programs.
>>
>> Phil Jeffrey
>> Princeton
>>
>>
> 
> 

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