> My second guess was that it might be 1/2*10/19*5/9*10/17*5/6 = > 0.071666093337919963306960210984979, or ~1 in 14, but is that > correct? Or does whether a previous draw is in the subset of 10 or > not matter?
If I'm thinking straight, you're getting close. The first card, since we only care about the 10 correct ones, has a chance of 10/20. The second has a chance of 9/19 -- because we've removed one correct card. So, if I'm right and not as befuddled as I commonly am, you end up with something like 0.016253869969..... The think to keep in mind is that since you only care about ones that hit every time, you can ignore all cases where one misses. --Ben ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~| Find out how CFTicket can increase your company's customer support efficiency by 100% http://www.houseoffusion.com/banners/view.cfm?bannerid=49 Message: http://www.houseoffusion.com/lists.cfm/link=i:5:142577 Archives: http://www.houseoffusion.com/cf_lists/threads.cfm/5 Subscription: http://www.houseoffusion.com/lists.cfm/link=s:5 Unsubscribe: http://www.houseoffusion.com/cf_lists/unsubscribe.cfm?user=89.70.5 Donations & Support: http://www.houseoffusion.com/tiny.cfm/54
