In the example below, I really want the cell with 14 in it to be empty, but
it is too much trouble to empty it and the one below it. But the answer I
get using "from" is different from the answer I get using 0 _1}. , which is
the answer I was trying for. But maybe you are on the right track. I am not
familiar enough with L. to quickly improve on your from.
I tried to invent a version of +/ &.:(<<< row;column){, but there is no
such take, much less an inverse of that take. Oh well...
r_webspread_
┌─┬─┬──┐
│1│3│14│
├─┼─┼──┤
│2│2│4 │
└─┴─┴──┘
from=: [: ($~ $-.1:) <@[ >^:L.@{ ]
+/ 0 from r_webspread_
18
+/ &:> {. 0 _1}.r_webspread_
4
+/ &:> {. r_webspread_
18
On Tue, Feb 25, 2014 at 3:29 PM, Raul Miller <[email protected]> wrote:
> Perhaps this would help:
>
> from=: [: ($~ $-.1:) <@[ >^:L.@{ ]
>
> +/ 0 from r
>
> ?
>
> Thanks,
>
> --
> Raul
>
>
>
> --
(B=)
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