As far as i know, for 2 * 6v batteries in series, you would require around 14.5V @ room temp to charge them both. You will need to limit the current some way or another, a resistor of sufficient size should do fine. The maximum charge current should be approximately less than or equal to the battery capasity in mAh divide by 3, but a 'standard' charge current should be around 10% of rated capasity. I've always known that charge time is equal to capasity * 1.4 divided by charge current but I would monitor the battery as it charges anyway. Just make sure the resistor you use can handle the power running through it.
Correct me if I'm wrong anyone :)
 
Regards,
Mikael
 
 
----- Original Message -----
Sent: Wednesday, December 04, 2002 12:32 PM
Subject: charging sealed lead acid batteries

I would like to replace a pair of 6v lantern batteries in a lantern with a sealed lead acid or gel cell battery and would like to know about charging them.  I figure I can apply 12.5-13.5 volts DC though a wall transformer, do I need to add a current limiting resister or have I got this all wrong?
 
Thanks
Jeremy

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