--- Mikael <[EMAIL PROTECTED]> wrote:
> As far as i know, for 2 * 6v batteries in series,
> you would require around 14.5V @ room temp to charge
> them both. You will need to limit the current some
> way or another, a resistor of sufficient size should
> do fine. The maximum charge current should be
> approximately less than or equal to the battery
> capasity in mAh divide by 3, but a 'standard' charge
> current should be around 10% of rated capasity. I've
> always known that charge time is equal to capasity *
> 1.4 divided by charge current but I would monitor
> the battery as it charges anyway. Just make sure the
> resistor you use can handle the power running
> through it.
> Correct me if I'm wrong anyone :)
> 
> Regards,
> Mikael


That�s correct. I would like to add:
1. The charging method for this type of accumulators
is constant voltage. The current limit is just for
protection.
2. Take care not to exceed 2.45V (at 20 degrees
Celsius) per cell. This will result in permanent lose
of electrolyte.
3. When dealing with accumulators it�s always
advisable to follow manufacturer�s rules.

Best regards,
Mircea


>   ----- Original Message ----- 
>   From: Jeremy N. E. Proffitt 
>   To: Multiple recipients of list CHIPDIR-L 
>   Sent: Wednesday, December 04, 2002 12:32 PM
>   Subject: charging sealed lead acid batteries
> 
> 
>   I would like to replace a pair of 6v lantern
> batteries in a lantern with a sealed lead acid or
> gel cell battery and would like to know about
> charging them.  I figure I can apply 12.5-13.5 volts
> DC though a wall transformer, do I need to add a
> current limiting resister or have I got this all
> wrong?
> 
>   Thanks
>   Jeremy
> 


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Author: Mircea Coman
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