What, precisely, happens if two threads sharing a reference to a single lazy sequence try to realize the same element at the same time? If the sequence is completely pure and deterministic, so any attempt to realize a particular element will produce a single particular value consistently (unlike, say, (repeatedly rand) or a file-seq where relevant parts of the filesystem are being concurrently modified), is the worst-case scenario that the two threads will redundantly perform the same calculation, with no effect other than a minor hit to performance and, in particular, no effect on the program semantics?
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