It corresponds to the execution of the LazySeq fn. That fn will be called
once and only once, the rest of the data in the object is immutable and
side-effect free and therefore does not need to be synchronized.

Timothy


On Mon, Jun 24, 2013 at 8:51 PM, Cedric Greevey <cgree...@gmail.com> wrote:

> I'm familiar with what "synchronized Type foo (args)" does -- my last
> question was more about what aspect of a lazy seq the object with the
> method corresponds to. Cons cell or similar subunit? I could read half of
> clojure.lang, learn how all the various types of seq (Cons, LazySeq,
> ChunkedSeq, etc...) work under the hood, and thereby eventually figure it
> out, but it's probably a lot fewer man-hours of work for me to ask someone
> who's already intimately familiar with that codebase and for him to
> answer...
>
>
>
> On Mon, Jun 24, 2013 at 10:32 PM, Timothy Baldridge 
> <tbaldri...@gmail.com>wrote:
>
>> Reading the LazySeq.java file should make this all clear, but yes, no
>> race conditions.
>>
>>
>> https://github.com/clojure/clojure/blob/master/src/jvm/clojure/lang/LazySeq.java#L37
>>
>> Synchronized methods basically lock the current instance of the object
>> while the method runs, so it is impossible for two threads to execute the
>> lazy seq fn at the same time.
>>
>> Timothy
>>
>>
>> On Mon, Jun 24, 2013 at 4:17 PM, Cedric Greevey <cgree...@gmail.com>wrote:
>>
>>> Ah, thanks. The locking granularity is local to the cons cell (or
>>> analogue; first/rest pair) being realized, I hope? So one thread actually
>>> calculates an element and neither call returns until it's calculated, and
>>> then both promptly return the calculated value, but threads realizing other
>>> lazy seqs or crawling along earlier parts of the same one don't get
>>> blocked? (And given they can share tails, how would "same one" even be
>>> defined anyway?)
>>>
>>>
>>> On Mon, Jun 24, 2013 at 5:56 PM, Nicola Mometto <brobro...@gmail.com>wrote:
>>>
>>>>
>>>> Realizing a lazy-seq is done through a synchronized method see:
>>>>
>>>> https://github.com/clojure/clojure/blob/master/src/jvm/clojure/lang/LazySeq.java#L37
>>>>
>>>> No race conditions.
>>>>
>>>> Cedric Greevey writes:
>>>>
>>>> > What, precisely, happens if two threads sharing a reference to a
>>>> single
>>>> > lazy sequence try to realize the same element at the same time? If the
>>>> > sequence is completely pure and deterministic, so any attempt to
>>>> realize a
>>>> > particular element will produce a single particular value consistently
>>>> > (unlike, say, (repeatedly rand) or a file-seq where relevant parts of
>>>> the
>>>> > filesystem are being concurrently modified), is the worst-case
>>>> scenario
>>>> > that the two threads will redundantly perform the same calculation,
>>>> with no
>>>> > effect other than a minor hit to performance and, in particular, no
>>>> effect
>>>> > on the program semantics?
>>>> >
>>>> > --
>>>>
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>>
>>
>>
>> --
>> “One of the main causes of the fall of the Roman Empire was that–lacking
>> zero–they had no way to indicate successful termination of their C
>> programs.”
>> (Robert Firth)
>>
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-- 
“One of the main causes of the fall of the Roman Empire was that–lacking
zero–they had no way to indicate successful termination of their C
programs.”
(Robert Firth)

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