Quincey,
That part works, but now I get an error on a line of code where multiplication
takes place. This error occurred after the change for suggested:
func linconv<T: FloatingPointType>(signal_A signal_A: [T], signal_B: [T]) ->
[T]? {
// guard
guard signal_A.isEmpty == false && signal_B.isEmpty == false else {
return nil
}
// reverse at least one of the arrays
//let signal_A_reversed = Array(signal_A.reverse())
// size of new array
let N = signal_A.count + signal_B.count - 1
// new array for result
var resultSignal = [T](count: N, repeatedValue: T(0))
for n in 0..<N {
for j in 0...n {
if j < signal_B.count && (n - j) < signal_A.count {
resultSignal[n] += (signal_B[j] * signal_A[n - j]) // error
here, cannot use binary operator ‘*'
}
}
}
return resultSignal
}
My head is starting to spin. Again, I do not see this one being any different
from the integer type version.
> On Dec 24, 2015, at 2:55 PM, Peters, Brandon <[email protected]> wrote:
>
> Quincey,
>
> I must have missed something small earlier. Tried it again and it works.
> Thank you...
>
> On Dec 24, 2015, at 12:28 PM, Quincey Morris
> <[email protected]<mailto:[email protected]>>
> wrote:
>
> On Dec 24, 2015, at 04:55 , Peters, Brandon
> <[email protected]<mailto:[email protected]>> wrote:
>
> I am using Xcode 7.2. What version of Xcode are you running? Unless I am
> missing something, the version you typed into playground is not working for
> me in code editor when I press run.
>
> Also 7.2. Here is exactly what I have in the playground, and it correctly
> shows the result as nil:
>
> func linconv<T: FloatingPointType>(signal_A signal_A: [T], signal_B: [T]) ->
> [T]? {
>
> var arr = [T](count: 4, repeatedValue: T(0))
>
> return nil
> }
>
> func linconv<T: IntegerType>(signal_A signal_A: [T], signal_B: [T]) -> [T]? {
>
> var arr = [T](count: 4, repeatedValue: 0)
>
> return nil
> }
>
> linconv (signal_A: [10.0], signal_B: [20.0])
>
>
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