Giacomo Tesio <giac...@tesio.it> writes: > The current construct is a violation of the GPL term as that code is > derivative of GPL code for all intents and purposes. So much that it > cannot even compile without the GPL code.
For the license of source code, it is not required that it compiles. And, taking out a portion of the code (a single algorithm or so) that does not depend on GPL code and to re-use it elsewehere is a normal and intended use for an open source program. It is one of the goals of having a program open source. And if the code is a modified copy (this is what the GPL actually protects), you should prove that: show the code in question, show the original (GPL) code and show how it was modified. Best Ole
