Hallo, John wrote (23 May 2003): > instead, the per-option quorum will throw out the IDW in > favour of a less-favoured option due to quorum requirements. > > R=15 > 10 ABD > 5 BDA
I suggest that one should at first calculate the ranking of the candidates according to the beat path method and then, of those candidates whose beat path to the default option meets the quorum, that candidate should be elected who is ranked highest in the ranking of the beat path method. That's the maximum that you can get without undermining the intention of super-majority requirements. Example: A:B=206:94 A:C=160:140 A:D=161:139 A:E=162:138 A:F=96:204 B:C=202:98 B:D=163:137 B:E=164:136 B:F=205:95 C:D=203:97 C:E=93:207 C:F=165:135 D:E=228:72 D:F=166:134 E:F=201:99 Via beat paths, the pairwise defeats are: A:B=206:204 A:C=202:201 A:D=202:201 A:E=202:201 A:F=205:204 B:C=202:201 B:D=202:201 B:E=202:201 B:F=205:204 C:D=203:207 C:E=203:207 C:F=201:202 D:E=228:203 D:F=201:202 E:F=201:202 Therefore, the ranking according to the beat path method is ABFDEC. Suppose that, for example, the default option is C and the quorum is 207. Then the winner is candidate D. Markus Schulze
