Re: [DUG] C code help

Thu, 13 Jul 2006 02:07:48 -0700

Just to clarify this a bit...
 
An audio file tag format uses 4 bytes to store a flag to indicate whether text or binary information is stored in the following tag.  The C++ source code uses these definitions
 
#define TAG_FIELD_FLAG_DATA_TYPE_MASK           (6)
#define TAG_FIELD_FLAG_DATA_TYPE_TEXT_UTF8      (0 << 1)
#define TAG_FIELD_FLAG_DATA_TYPE_BINARY         (1 << 1)
#define TAG_FIELD_FLAG_DATA_TYPE_EXTERNAL_INFO  (2 << 1)
#define TAG_FIELD_FLAG_DATA_TYPE_RESERVED       (3 << 1)
 
Am I correct in assuming that a Binary flag will appear like this in the file (in Hex).
 
00 00 00 02
 
Effectively a big endian value of 02.  Is this correct?
 
Thanks,
Ross.
----- Original Message -----
From: Ross Levis
Sent: Thursday, July 13, 2006 8:17 PM
Subject: Re: [DUG] C code help

> So TAG_FIELD_FLAG_DATA_TYPE is a one-bit flag stored in the 2nd-rightmost bit of the word, and its possible values are TEXT_UTF8 (value 0) and BINARY (value 1).
 
I see.  Thanks for that.
 
Cheers,
Ross.
----- Original Message -----
Sent: Thursday, July 13, 2006 7:32 PM
Subject: Re: [DUG] C code help

That's the bitwise shift-left operator. So, 0 shifted left 1 bit is still zero, 1 shifted left 1 bit is 2. 1 shifted left 30 bits would be (hex) 40000000.
 
Brian

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