Direct translation:

const
 TAG_FIELD_FLAG_DATA_TYPE_MASK = 6;
 TAG_FIELD_FLAG_DATA_TYPE_TEXT_UTF8 = 0 shl 1;
 TAG_FIELD_FLAG_DATA_TYPE_BINARY= 1 shl 1;
 TAG_FIELD_FLAG_DATA_TYPE_EXTERNAL_INFO = 2 shl 1;
 TAG_FIELD_FLAG_DATA_TYPE_RESERVED = 3 shl 1;


----- Original Message ----- From: "Ross Levis" <[EMAIL PROTECTED]>
To: "NZ Borland Developers Group - Delphi List" <[email protected]>
Sent: Thursday, July 13, 2006 9:07 PM
Subject: Re: [DUG] C code help


Just to clarify this a bit...

An audio file tag format uses 4 bytes to store a flag to indicate whether text or binary information is stored in the following tag. The C++ source code uses these definitions

#define TAG_FIELD_FLAG_DATA_TYPE_MASK           (6)
#define TAG_FIELD_FLAG_DATA_TYPE_TEXT_UTF8      (0 << 1)
#define TAG_FIELD_FLAG_DATA_TYPE_BINARY         (1 << 1)
#define TAG_FIELD_FLAG_DATA_TYPE_EXTERNAL_INFO  (2 << 1)
#define TAG_FIELD_FLAG_DATA_TYPE_RESERVED       (3 << 1)

Am I correct in assuming that a Binary flag will appear like this in the file (in Hex).

00 00 00 02

Effectively a big endian value of 02.  Is this correct?

Thanks,
Ross.
----- Original Message ----- From: Ross Levis
 To: NZ Borland Developers Group - Delphi List
 Sent: Thursday, July 13, 2006 8:17 PM
 Subject: Re: [DUG] C code help


> So TAG_FIELD_FLAG_DATA_TYPE is a one-bit flag stored in the 2nd-rightmost bit of the word, and its possible values are TEXT_UTF8 (value 0) and BINARY (value 1).

 I see.  Thanks for that.

 Cheers,
 Ross.
----- Original Message ----- From: Brian Wrigley
   To: NZ Borland Developers Group - Delphi List
   Sent: Thursday, July 13, 2006 7:32 PM
   Subject: Re: [DUG] C code help


That's the bitwise shift-left operator. So, 0 shifted left 1 bit is still zero, 1 shifted left 1 bit is 2. 1 shifted left 30 bits would be (hex) 40000000.

   Brian


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