On Saturday, 13 June 2015 at 17:37:31 UTC, anonymous wrote:
Please show how it is not. Seems to work just fine.
OK. Still, this method works:
char[][][][][][] strArr = [[[[["foo", "baz"], ["bar",
"tor"]]]].to!(char[][][][][])];
But I don't want to write this `.to!(char[][][][][])`.
On Saturday, 13 June 2015 at 17:37:31 UTC, anonymous wrote:
Your definitions of "something like that" and "other ways" are
unreasonably narrow, in my opinion. Typing out ".dup" is D's
way to do mutable strings. You just don't like it.
Yes, I don't like it.
