On Tuesday, 11 October 2016 at 19:46:31 UTC, Jon Degenhardt wrote:
On Tuesday, 11 October 2016 at 18:18:41 UTC, ag0aep6g wrote:
On 10/11/2016 06:24 AM, Jon Degenhardt wrote:
The example I gave uses ref parameters. On the surface it
would seem
reasonable to that passing a static array by ref would allow
it to be
modified, without having to slice it first.
Your ref parameters are only for the per-element operations.
You're not passing the array as a whole by reference. And you
can't, because `each` itself takes the whole range by copy.
So, the by-ref increments themselves do work, but they're
applied to a copy of your original static array.
I see. Thanks for the explanation. I wasn't thinking it through
properly. Also, I guess I had assumed that the intent was that
each! be able to modify the elements, and therefore the whole
array it would be pass by reference, but didn't consider it
properly.
Another perspective where the current behavior could be confusing
is that it is somewhat natural to assume that 'each' is the
functional equivalent of foreach, and that they can be used
interchangeably. However, for static arrays they cannot be.