Steven Schveighoffer wrote:
it seems that the only difference between `void` and `double` lambda is one
asm instruction: `fldl (%edi)`. it is presend in `double` labmda, and
absent in `void` lambda.
it looks like ignoring `double` result causes FPU stack imbalance ('cause
compiler doesn't insert "FPU pop" instruction), and that affects the computations.
on 64 bit it doesn't matter, 'cause no FPU is used there.
the fix prolly should be easy: just emit "FPU pop" if function result is
ignored. codegen should have this info at hand, i believe.
