On Thursday, 12 April 2018 at 21:17:30 UTC, Paul Backus wrote:
On Thursday, 12 April 2018 at 20:34:40 UTC, Chris Katko wrote:
But each doesn't return anything, it mutates, right? I think
that's the problem I ran into with my attempt. With your code,
I get an error about void:
string []x = split(file.readln.idup, " ");
x.each((ref s) => s.each((ref n) => n.stripRight()));
You need to put an exclamation point after 'each' to pass the
function as a template parameter:
x.each!((ref s) => s.each!((ref n) => n.stripRight()));
DOH.
But now I'm here:
extra.d(2493): Error: template extra.map_t.load_map2.each!((ref
s) => s.each!((ref n) => n.stripRight())).each cannot deduce
function from argument types !()(string[]), candidates are:
/usr/include/dmd/phobos/std/algorithm/iteration.d(899):
extra.map_t.load_map2.each!((ref s) => s.each!((ref n) =>
n.stripRight())).each(Range)(Range r) if
(!isForeachIterable!Range && (isRangeIterable!Range ||
__traits(compiles, typeof(r.front).length)))
/usr/include/dmd/phobos/std/algorithm/iteration.d(934):
extra.map_t.load_map2.each!((ref s) => s.each!((ref n) =>
n.stripRight())).each(Iterable)(auto ref Iterable r) if
(isForeachIterable!Iterable || __traits(compiles,
Parameters!(Parameters!(r.opApply))))
From:
string []x = split(file.readln.idup, " ");
import std.algorithm;
x.each!((ref s) => s.each!((ref n) => n.stripRight()));
Looks like it can't tell if it's a Range or... an auto ref
Iterable?
