On 04/12/2018 02:22 PM, Chris Katko wrote:
On Thursday, 12 April 2018 at 21:17:30 UTC, Paul Backus wrote:
On Thursday, 12 April 2018 at 20:34:40 UTC, Chris Katko wrote:
But each doesn't return anything, it mutates, right? I think that's
the problem I ran into with my attempt. With your code, I get an
error about void:
string []x = split(file.readln.idup, " ");
x.each((ref s) => s.each((ref n) => n.stripRight()));
You need to put an exclamation point after 'each' to pass the function
as a template parameter:
x.each!((ref s) => s.each!((ref n) => n.stripRight()));
DOH.
But now I'm here:
extra.d(2493): Error: template extra.map_t.load_map2.each!((ref s) =>
s.each!((ref n) => n.stripRight())).each cannot deduce function from
argument types !()(string[]), candidates are:
/usr/include/dmd/phobos/std/algorithm/iteration.d(899):
extra.map_t.load_map2.each!((ref s) => s.each!((ref n) =>
n.stripRight())).each(Range)(Range r) if (!isForeachIterable!Range &&
(isRangeIterable!Range || __traits(compiles, typeof(r.front).length)))
/usr/include/dmd/phobos/std/algorithm/iteration.d(934):
extra.map_t.load_map2.each!((ref s) => s.each!((ref n) =>
n.stripRight())).each(Iterable)(auto ref Iterable r) if
(isForeachIterable!Iterable || __traits(compiles,
Parameters!(Parameters!(r.opApply))))
From:
string []x = split(file.readln.idup, " ");
import std.algorithm;
x.each!((ref s) => s.each!((ref n) => n.stripRight()));
Looks like it can't tell if it's a Range or... an auto ref Iterable?
Assuming the file "2darray" includes
0 1 15 0 0
2 12 1 0 0
0 1 0 10 0
the following program produces a range of ranges that produce the
intended integer values:
import std.stdio;
import std.algorithm;
import std.conv;
void main() {
auto file = File("2darray");
auto r = file.byLine.map!(l => l.splitter.map!(to!int));
writefln("%(%s\n%)", r);
}
The output is
[0, 1, 15, 0, 0]
[2, 12, 1, 0, 0]
[0, 1, 0, 10, 0]
If you want to produce an actual 2d array, you can add two .array calls
at that chain:
import std.range : array;
auto r = file.byLine.map!(l => l.splitter.map!(to!int).array).array;
Ali
