On 07/01/2013 03:44 PM, Ary Borenszweig wrote:
On 6/30/13 10:56 PM, Timon Gehr wrote:
On 07/01/2013 03:08 AM, Kenji Hara wrote:
2013/7/1 JS <[email protected] <mailto:[email protected]>>
I am simply talking about having the compiler enlarge the type if
needed. (this is mainly for built in types since the type hierarchy
is explicitly known)
Just a simple matter, it would *drastically* increase compilation time.
void foo()
{
auto elem;
auto arr = [elem];
elem = 1;
....
elem = 2.0;
// typeof(elem) change should modify the result of typeof(arr)
}
Such type dependencies between multiple variables are common in the
realistic program.
When `elem = 2.0;` is found, compiler should run semantic analysis of
the whole function body of foo _once again_, because the setting type of
elem ignites the change of typeof(arr), and it would affect the code
meaning.
If another variable type would be modified, it also ignites the whole
function body semantic again.
After all, semantic analysis repetition would drastically increase.
I can easily imagine that the compilation cost would not be worth the
small benefits.
Kenji Hara
The described strategy can easily result in non-termination, and which
template instantiations it performs can be non-obvious.
auto foo(T)(T arg){
static if(is(T==int)) return 1.0;
else return 1;
}
void main(){
auto x;
x = 1;
x = foo(x);
}
Just tried it in Crystal
Using overloaded functions, I guess? It is not really the same thing,
because those need to be type checked in any case.
and it ends alright.
(Note that I was specifically addressing the method Kenji Hara lined
out, which appears to completely restart type checking every time a type
changes.)
It works like this:
1. x is an Int
2. you call foo(x), it returns a float so x is now a float (right now in
Crystal that's a union of int and float, but that will soon change).
3. Since x is a float, foo returns an int, but assigning it to x, which
is already a float, gives back a float.
4. No type changed, so we end.
...
This kind of fixed-point iteration will terminate in D in most relevant
cases (it is possible to create an infinitely ascending chain of types,
but then, type checking failing implicit conversions won't terminate
anyway).
But note that now x is a double even though it is only assigned ints.
Furthermore, this approach still implicitly instantiates template
versions that are not referred to in the final type checked code.