On Friday, 30 September 2016 at 03:07:41 UTC, Mike Parker wrote:
On Friday, 30 September 2016 at 01:48:02 UTC, Jacob wrote:
auto* pValue = expr; // still invalid code unless expr
evaluate to a pointer type
auto* pValue = &expr; // this is valid if expr is a ref
It still requires the &, what it prevents is this situation:
auto pValue = expr; // wanted pointer, expr evaluates to
non-ptr value through change of code or simply forgetting "&"
So no code should be broken, you can do everything the same
way without a change in behavior and auto with a "*" is
currently invalid.
Basically how it works in C++: http://ideone.com/TUz9dO
You could forget the * just as easily as the &.
Easier to notice and to check whether the type is a pointer.
