On Tue, 08 Nov 2011 19:09:40 +0200, deadalnix <[email protected]> wrote:
You'll face a problem when it come to define variable within the function and not in its definition.I'm affraid this will become very confusing in this case.
inout fun(inout) {
inout var; // This is what you are saying i believe.
....
}
You are definitely right, if this use case was intended.
